![Treceti in baza 2 nr. natural: n=[3^3+(3^9×4-3^9)÷9^4-3^0]÷[(5×5^2×5^3)^4÷5^ 23]= - Brainly.ro](https://ro-static.z-dn.net/files/d10/5ea1b9443abe10ae2769b3299857fdb3.png "Treceti in baza 2 nr. natural: n=[3^3+(3^9×4-3^9)÷9^4-3^0]÷[(5×5^2×5^3)^4÷5^ 23]= - Brainly.ro")
Treceti in baza 2 nr. natural: n=[3^3+(3^9×4-3^9)÷9^4-3^0]÷[(5×5^2×5^3)^4÷5^ 23]= - Brainly.ro
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