![calculus - Maximum value of $\frac{a}{1+bc} + \frac b{1+ac} + \frac{c}{1+ab}$ given $a^2 + b^2 + c^2 = 1$ - Mathematics Stack Exchange calculus - Maximum value of $\frac{a}{1+bc} + \frac b{1+ac} + \frac{c}{1+ab}$ given $a^2 + b^2 + c^2 = 1$ - Mathematics Stack Exchange](https://i.stack.imgur.com/740Nr.png)
calculus - Maximum value of $\frac{a}{1+bc} + \frac b{1+ac} + \frac{c}{1+ab}$ given $a^2 + b^2 + c^2 = 1$ - Mathematics Stack Exchange
In ∆ABC, D is the midpoint of BC and AE⊥BC. If AC>AB, show that AB^2 = AD^2 + 1/4 BC^2 - BC.DE - Sarthaks eConnect | Largest Online Education Community
![If a circle touches the side BC of a triangle ABC at P and extended sides AB and AC at Q and R, respectively, prove that AQ = 1/2 (BC + CA + AB) If a circle touches the side BC of a triangle ABC at P and extended sides AB and AC at Q and R, respectively, prove that AQ = 1/2 (BC + CA + AB)](https://d138zd1ktt9iqe.cloudfront.net/media/seo_landing_files/if-a-circle-touches-the-side-bc-of-a-triangle-abc-at-p-and-extended-sides-ab-and-ac-at-q-and-r-1643385893.png)
If a circle touches the side BC of a triangle ABC at P and extended sides AB and AC at Q and R, respectively, prove that AQ = 1/2 (BC + CA + AB)
![In given figure ABC is a triangle in which AB = AC and D is any point in BC. Prove that AB^2 - AD^2 = BD.CD In given figure ABC is a triangle in which AB = AC and D is any point in BC. Prove that AB^2 - AD^2 = BD.CD](https://dwes9vv9u0550.cloudfront.net/images/3778880/eb0fdf58-36d3-4dd9-ba52-9c6285f15a9c.jpg)
In given figure ABC is a triangle in which AB = AC and D is any point in BC. Prove that AB^2 - AD^2 = BD.CD
SOLUTION: GIVEN A TRIANGLE ABC WHERE THE VALUE OF BC^2 =370 UNITS AC^2 =74 AND AB^2=116 CALCULATE THE AREA OF A TRIANGLE / HINT; 370=9^2+17^2,74 = 5^2 +7^2 AND 116 =4^2+10^2
![In ∆Abc, ∠C is an Obtuse Angle. Ad ⊥ Bc and Ab2 = Ac2 + 3 Bc2. Prove that Bc = Cd. - Mathematics | Shaalaa.com In ∆Abc, ∠C is an Obtuse Angle. Ad ⊥ Bc and Ab2 = Ac2 + 3 Bc2. Prove that Bc = Cd. - Mathematics | Shaalaa.com](https://www.shaalaa.com/images/_4:0133406892e64e04ac5f12b031ed8436.png)
In ∆Abc, ∠C is an Obtuse Angle. Ad ⊥ Bc and Ab2 = Ac2 + 3 Bc2. Prove that Bc = Cd. - Mathematics | Shaalaa.com
![In ΔABC, if AB = (2a-1)cm. AC = 2 √2acm. And BC = (2a + 1)cm., then let us write the value of ∠ BAC. In ΔABC, if AB = (2a-1)cm. AC = 2 √2acm. And BC = (2a + 1)cm., then let us write the value of ∠ BAC.](https://static.insightsonindia.in/ncertusercontent/solutions/?domain=gF&l=PROJ20900/1535801466322517.jpg)
In ΔABC, if AB = (2a-1)cm. AC = 2 √2acm. And BC = (2a + 1)cm., then let us write the value of ∠ BAC.
Prove Euclid's right traingle Theorem 1 and 2: ET_1 =>\overline{BC}^{2} = \overline{AC}*\overline{CH}; ET'_1 =>bar(AB)^{2} =bar(AC)*bar(AH); ET_2 =>barAH^{2} = \overline{AH}*\overline{CH}? ![enter image source here](https | Socratic
lf in ΔABC, AD is median and AE ⊥ BC, then prove that AB^2 + AC^2 = 2AD^2 + 1 / 2 BC^2. - Sarthaks eConnect | Largest Online Education Community
![A student made the following chart to prove that AB2 + BC2 = AC2. Statement Justification 1. - Brainly.com A student made the following chart to prove that AB2 + BC2 = AC2. Statement Justification 1. - Brainly.com](https://us-static.z-dn.net/files/da7/6c5ab9287f4a47af45c7c1b0fcd25e07.png)
A student made the following chart to prove that AB2 + BC2 = AC2. Statement Justification 1. - Brainly.com
![In any triangle ABC, prove that `AB^2 + AC^2 = 2(AD^2 + BD^2)` , where D is the midpoint of BC. - YouTube In any triangle ABC, prove that `AB^2 + AC^2 = 2(AD^2 + BD^2)` , where D is the midpoint of BC. - YouTube](https://i.ytimg.com/vi/wu1SuC41ez4/maxresdefault.jpg)