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ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB² = BC.BD ( ii) AC² = BC.DC (iii) AD² = BD.CD
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Ex 6.6, 4 (Optional) - ABC is a triangle, ABC < 90. Prove AC2 = AB2
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In Figure 2, AD | BC. Prove that AB^2 + CD^2 = BD^2 + AC^2.
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In any triangle ABC, prove that AB^2 + AC^2 = 2(AD^2 + BD^2) , where D is the midpoint of BC.
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Example 10 - ACB = 90 and CD perpendicular AB. Prove BC2/AC2
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Given : AC is perpendicular to BD.Prove : AB^2 + CD^2 = BC^2 + AD^2
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geometry - To prove in a triangle: $AD^2=AB\cdot AC- BD\cdot CD$ - Mathematics Stack Exchange