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![Calculate the mean free path in CO2 at 27^∘C and a pressure of 10^-9 bar. Molecular diameter of CO2 is 500 pm.[ Given : R = 25/3 J.mol^-1K^-1, √(2) = 1.4, pi = 22/7, NA = 6 × 10^23 ]](https://toppr-doubts-media.s3.amazonaws.com/images/4700975/dc175a27-4ab9-44ce-88e1-7d9b75e43184.jpg "Calculate the mean free path in CO2 at 27^∘C and a pressure of 10^-9 bar. Molecular diameter of CO2 is 500 pm.[ Given : R = 25/3 J.mol^-1K^-1, √(2) = 1.4, pi = 22/7, NA = 6 × 10^23 ]")
Calculate the mean free path in CO2 at 27^∘C and a pressure of 10^-9 bar. Molecular diameter of CO2 is 500 pm.[ Given : R = 25/3 J.mol^-1K^-1, √(2) = 1.4, pi = 22/7, NA = 6 × 10^23 ]
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